MCQ
A particle experiences a constant acceleration for $20 \,sec$ after starting from rest. If it travels a distance ${S_1}$ in the first $10\, sec$ and a distance ${S_2}$ in the next $10 \,sec$, then
  • A
    ${S_1} = {S_2}$
  • ${S_1} = {S_2}/3$
  • C
    ${S_1} = {S_2}/2$
  • D
    ${S_1} = {S_2}/4$

Answer

Correct option: B.
${S_1} = {S_2}/3$
b
(b) As $S = ut + \frac{1}{2}a{t^2}$

$\therefore {S_1} = \frac{1}{2}a{(10)^2} = 50a$ .....(i)

$As\;\;v = u + at$

$\therefore $ velocity acquired by particle in $10 \,sec$ $v = a \times 10$

For next $10\, sec$ ,

${S_2} = (10a) \times 10 + \frac{1}{2}(a) \times {(10)^2}$

${S_2} = $ $150a$ .....(ii)

From (i) and (ii)

${S_1} = {S_2}/3$

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