MCQ
A particle experiences a constant acceleration for $20 sec$ after starting from rest. If it travels a distance $S_1$ in the first $10 sec$ and a distance $S_2$ in the next $10 sec$, then
  • A
    $S_1=S_2$
  • $S_1=S_2 / 3$
  • C
    $S_1=S_2 / 2$
  • D
    $S_1=S_2 / 4$

Answer

Correct option: B.
$S_1=S_2 / 3$
(b) As $S=u t+\frac{1}{2} a t^2 \therefore S_1=\frac{1}{2} a(10)^2=50 a$As $v=u+$ at $\therefore$ velocity acquired by particle in $10 \mathrm{sec}$ $v=a \times 10$For next $10 \mathrm{sec}, \quad S_2=(10 a) \times 10+\frac{1}{2}(a) \times(10)^2$$S_2=150 a$From (i) and (ii) $S_1=S_2 / 3$

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