MCQ
A particle initially at rest moves along the $x$-axis. Its acceleration varies with time as $a=4\,t$. If it starts from the origin, the distance covered by it in $3\,s$ is $...........\,m$
- A$12$
- ✓$18$
- C$24$
- D$36$
Integrating,
$v=\frac{4 t^2}{2}=2 t^2$
again integrating
$d=\frac{2 t^3}{3}$
$t=3$
$d=\frac{2 \times 27}{3}=2 \times 9=18$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


$(1)$ $|\Delta \phi|$ remains the same if the parabolic wire is replaced by a straight wire, $y=x$ initially, of length $\sqrt{2} L$
$(2)$ $|\Delta \phi|$ is proportional to the length of the wire projected on the $y$-axis.
$(3)$ $|\Delta \phi|=\frac{1}{2} B _0 V _0 L$ for $\beta=0$
$(4)$ $|\Delta \phi|=\frac{4}{3} B_0 V_0 L$ for $\beta=2$