A particle is executing simple harmonic motion $(SHM)$ of amplitude $A,$ along the $x-$ axis, about $x = 0.$ When its potential energy $(PE)$ equals kinetic energy $(KE),$ the position of the particle will be
  • A$\frac {A}{2}$
  • B$\frac {A}{2\sqrt 2}$
  • C$\frac {A}{\sqrt 2}$
  • D$A$
JEE MAIN 2019, Medium
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