Question
A particle is moving along a straight line parallel to $x-$ axis with constant velocity. Its angular momentum about the origin
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Answer
$\overrightarrow{\mathrm{L}}=\mathrm{m}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{r}})=\operatorname{mv}[\mathrm{rsin} \theta]=\mathrm{mvh}=\mathrm{constant}$
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