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3.2 , motion in plane — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics3.2 , motion in plane1 Mark
MCQ
A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a = (4\hat i + 3\hat j)\ m/s^2$ and $\vec p = (8\hat i - 6\hat j)\ kg-m/s$ . The motion of the particle is
  • A
    uniform circular motion
  • ✓
    accelerated circular motion
  • C
    de-accelerated circular motion
  • D
    we can not say anything with $\vec a$ and $\vec p$ only
✓

Answer

Correct option: B.
accelerated circular motion
b
$\vec{a}=4 \hat{i}+3 \hat{j}$

$\vec{P}=8 \hat{i}-6 \hat{j}$

$a_{c}=\frac{V^{2}}{R}=4$

$a_{t}=\left(\frac{d V}{d t}\right)=3$

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