MCQ
A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angles $30^o $ and $60^o $ from vertical (lowest position) are $T_1 and T_2$ respectively. then
  • A
    $T_1 = T_2$
  • B
    $T_2 > T_1$
  • $T_1 > T_2$
  • D
    Tension in the string always remains the same

Answer

Correct option: C.
$T_1 > T_2$
c
(c) Tension, $T = \frac{{m{v^2}}}{r} + mg\cos \theta $

For, $\theta = 30^\circ ,{T_1} = \frac{{m{v^2}}}{r} + mg\cos 30^\circ $

$\theta = 60^\circ ,{T_2} = \frac{{m{v^2}}}{r} + mg\cos 60^\circ $

$\therefore {T_1} > {T_2}$

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