The upper half of an inclined plane of inclination theta is perfectly smooth while the lower half is rough. A body starting from the rest

Q: The upper half of an inclined plane of inclination $\theta$ is perfectly smooth while the lower half is rough. A body starting from the rest at top comes back to rest at the bottom if the coefficient of friction for the lower half is given by

d (d) For upper half ${v^2} = {u^2} + 2al/2 = 2(g\sin \theta )l/2 = gl\sin \theta $ For lower half $⇒$ $0 = {u^2} + 2g(\sin \theta - \mu \cos \theta )\frac{l}{2}$ $⇒$ $ - gl\sin \theta = gl(\sin \theta - \mu \cos \theta )$ $⇒$ $\mu \cos \theta = 2\sin \theta \Rightarrow \mu = 2\tan \theta $

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

The upper half of an inclined plane of inclination $\theta$ is perfectly smooth while the lower half is rough. A body starting from the rest at top comes back to rest at the bottom if the coefficient of friction for the lower half is given by

A$µ = sin$$\theta$
B$µ = cot$$\theta$
C$µ = 2\, cos$$\theta$
D$µ = 2 \,tan$$\theta$

AIEEE 2005, Diffcult

STD 11 Science
NEET
STD 11 - 4.2. friction
Physics

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