MCQ
A particle is moving on a circular path with constant speed $v$. It moves between two points $A$ and $B$. which subtends an angle $60^{\circ}$ at the centre of circle. The magnitude of change in its velocity and change in magnitude of its velocity during motion from $A$ to $B$ are respectively ..........
  • A
    $0,0$
  • $v, 0$
  • C
    $0, v$
  • D
    $2 v, v$

Answer

Correct option: B.
$v, 0$
b
(b)

$\Delta v=2 v \sin \frac{\theta}{2}$

$=2 v \times \sin \left(\frac{60}{2}\right)$

$|\Delta v|=v$

Change in magnitude of velocity $=0$

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