A particle is performing simple harmonic motion
$(i)$ its velocity-displacement graph is parabolic in nature
$(ii)$ its velocity-time graph is sinusoidal in nature
$(iii)$ its velocity-acceleration graph is elliptical in nature
Correct answer is
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$(i)$ $\mathrm{v}=\omega \sqrt{\mathrm{A}^{2}-\mathrm{x}^{2}}$ $(ii)$ $\mathrm{v}=\mathrm{A} \omega \cos \omega \mathrm{t}$

$\mathrm{v}=\mathrm{A} \omega \cos \omega \mathrm{t} ; \mathrm{a}=\mathrm{A} \omega^{2} \sin \omega \mathrm{t}$

$\Rightarrow \frac{v^{2}}{A^{2} \omega^{2}}+\frac{a^{2}}{A^{2} \omega^{4}}=1$

$(ii)$ and $(iii)$ are correct

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