Question
A particle is projected upwards. The times corresponding to height $h$ while ascending and while descending are $t‌‌_1$ and $t_2$ respectively. The velocity of projection will be

Answer

(d) If ${t_1}$ and ${t_2}$ are time of ascent and descent respectively then time of flight $T = {t_1} + {t_2} = \frac{{2u}}{g}$

==> $u = \frac{{g({t_1} + {t_2})}}{2}$

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