MCQ
A particle is revolving in a circular path of radius $25 \,m$ with constant angular speed $12 \,rev/min$. Then the angular acceleration of particle is .......... $rad / s ^2$
- A$2 \pi^2$
- B$4 \pi^2$
- C$\pi^2$
- ✓$0$
✓
Answer
Correct option: D.
$0$
d
(d)
(d)
Angular acceleration is the rate of change of angular speed or angular velocity if $\vec{\omega}$ remains constant then
$\alpha=0$
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