MCQ
A particle moves along a circle with a constant angular speed $\omega$ Its displacement,with respect to this position of the particle at time $t = 0$ is plotted against time. The graph would look like
- A
- B
- ✓
- D
✓
Answer
Correct option: C.
c
$S = 2Rsin (\frac{\omega t}{2})$
$S = 2Rsin (\frac{\omega t}{2})$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$70$ calories of heat are required to raise the temperature of $2$ moles of an ideal gas at constant pressure from $30°C$ to $35°C.$ The amount of heat required to raise the temperature of same gas through the same range $(30°C$ to $35°C)$ at constant volume ..... $cal$ $(R = 2 \,cal/mol/K)$
→The displacement $y$ of a wave travelling in the x-direction is given by $y = {10^{ - 4}}\sin \,\,\left( {600t - 2x + \frac{\pi }{3}} \right)$ metres, where $x$ is expressed in metres and $t$ in seconds. The speed of the wave-motion, in ..... $ms^{-1}$, is
→A steel ball is released from rest a distance above a rigid horizontal surface and bounces several time. The diagram shows how its velocity varies with time. Which statement correctly explains why the areas $X$ and $Y$ are equal?
→A liquid of mass m and specific heat $c$ is heated to a temperature $2T.$ Another liquid of mass $m/2$ and specific heat $2c$ is heated to a temperature $T.$ If these two liquids are mixed, the resulting temperature of the mixture is
→The following phenomenon cannot be observed for sound waves
A spring of force constant $800\, N/m$ has an extension of $5\,cm$. The work done in extending it from $ 5\,cm$ to $15 \,cm$ is ............. $\mathrm{J}$
→A drop of water of volume $0.05\, cm^3$ is pressed between two glass plates, as a consequence of which it spreads and occupies an area of $40\, cm^2$. If the surface tension of water is $70\, dyne/cm$, then the normal force required to separate out the two glass plates will be in Newton
→The displacement of a particle moving in $S.H.M.$ at any instant is given by $y = a\sin \omega t$. The acceleration after time $t = \frac{T}{4}$ is (where $T$ is the time period)
→Identify the wrong statement:
An elevator car, whose floor to ceiling distance is equal to $2.7 \,m$, starts ascending with constant acceleration of $1.2 \;ms^{-2}$. $2 \,sec$ after the start, a bolt begins fallings from the ceiling of the car. The free fall time of the bolt is.........$s$
→