MCQ
A particle moves along an arc of a circle of radius $R$ . Its velocity depends on the distance covered as $v = a\sqrt s$ , where $a$ is a constant then the angle $\alpha $ between the vector of the total acceleration and the vector of velocity as a function of $s$ will be
- A$\tan \alpha = \frac{R}{{2s}}$
- ✓$\tan \alpha = \frac{2s}{{R}}$
- C$\tan \alpha = \frac{2R}{{s}}$
- D$\tan \alpha = \frac{s}{{2R}}$
