A particle of mass $250\,g$ executes a simple harmonic motion under a periodic force $F =(-25\,x) N$. The particle attains a maximum speed of $4\,m / s$ during its oscillation. The amplitude of the motion is $...........cm$.
JEE MAIN 2023, Medium
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$\frac{1}{4} a =-25 x \quad ; \quad a =-100 x$
$\omega^2=100 \quad \omega=10$
$\omega A =4$ $\quad A=\frac{4}{10}=0.4\,m$
$A =40\,cm$
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