MCQ
A particle of mass $m$ travelling along $x-$ axis with speed $v_0$ shoots out $1/3^{rd}$ of its mass with a speed $2v_0$ along $y-$ axis. The velocity of remaining piece is
  • ${v_0}\left( {\frac{3}{2}\hat i - \hat j} \right)$
  • B
    $\frac{{{v_0}}}{2}\left( {3\hat i - \hat j} \right)$
  • C
    ${v_0}\left( {\frac{1}{2}\hat i - 3\hat j} \right)$
  • D
    $\frac{{{v_0}}}{2}\left( {\hat i + 3\hat j} \right)$

Answer

Correct option: A.
${v_0}\left( {\frac{3}{2}\hat i - \hat j} \right)$
a
$\mathrm{m} \vec{\mathrm{u}_{1}}=\mathrm{m}_{1} \vec{\mathrm{v}}_{1}+\mathrm{m}_{2} \vec{\mathrm{v}}_{2}$

$\mathrm{mv}_{0} \hat{\mathrm{i}}=\frac{\mathrm{m}}{3}\left(2 \mathrm{v}_{0} \hat{\mathrm{j}}\right)+\frac{2 \mathrm{m}}{3} \mathrm{\vec v}_{2}$

$\vec{\mathrm{v}_{2}}=\frac{3}{2} \mathrm{v}_{0} \hat{\mathrm{i}}-\mathrm{v}_{0} \hat{\mathrm{j}}$

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