Question
A particle on a rotating disc have initial and final angular positions are
  1. -2 rad, +6 rad.
  2. -4 rad, -8 rad.
  3. 6 rad, -2 rad.
In which case, particle undergoes a negative displacement

Answer

  1. Angular displacement is $\Delta\theta=\theta_{\text{f}}-\theta_{\text{i}}=6-(-2)=8\text{rad}$
  2. $\Delta\theta=\theta_{\text{f}}-\theta_{\text{i}}$

$=-8\text{rad}-(-4\text{rad})=-4\text{rad}$

  1. $\Delta\theta=-2\text{rad}-(+6\text{rad})=-8\text{rad}$

In cascs (ii) ad (iii), angular displacement is negative.

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