MCQ
A particle performing uniform circular motion has angular momentum L. If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is:
- A$4\text{L}$
- B$\frac{\text{L}}{2}$
- C$\frac{\text{L}}{4}$
- D$2\text{L}$
✓
Answer
- $\frac{\text{L}}{4}$
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