A particle starts rotating from rest. Its angular displacement is… - Vidyadip

MCQ

A particle starts rotating from rest. Its angular displacement is expressed by the following equation $\theta = 0.025{t^2} - 0.1t$ where $\theta $ is in radian and $t $ is in seconds. The angular acceleration of the particle is

A
$0.5 \,rad/$$sec^2$ at the end of $10 \,sec$
B
$0.3 \,rad/$$sec^2$ at the end of $2 \,sec$
C
$0.05\, rad/$$sec^2$at the end of $1 \,sec$
✓
Constant $0.05,\ rad/$$sec^2$

✓

Answer

Correct option: D.

Constant $0.05,\ rad/$$sec^2$

d
$\alpha=\frac{d w}{d t}=\frac{d^{2} 0}{d t^{2}}$

$\frac{d \emptyset}{d t}=2 \times 0.025 t-0.1$

$\frac{d^{2} \theta}{d t}=0.05$

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