A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20\; m/s^2$ at a distance of $5\; m$ from the mean position. The time period of oscillation is
NEET 2018, Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1If a simple harmonic oscillator has got a displacement of $0.02\, m$ and acceleration equal to $2.0\,m{s^{ - 2}}$ at any time, the angular frequency of the oscillator is equal to .... $rad\,{s^{ - 1}}$View Solution
- 2The potential energy of a simple harmonic oscillator of mass $2\, kg$ in its mean position is $5\, J.$ If its total energy is $9\,J$ and its amplitude is $0.01\, m,$ its time period would beView Solution
- 3View SolutionA tunnel has been dug through the centre of the earth and a ball is released in it. It will reach the other end of the tunnel after
- 4If the time period of a two meter long simple pendulum is $2\, s$, the acceleration due to gravity at the place where pendulum is executing $S.H.M.$ isView Solution
- 5A mass $m$ attached to free end of a spring executes SHM with a period of $1\; s$. If the mass is increased by $3\; kg$ the period of oscillation increases by one second, the value of mass $m$ is $..............kg$.View Solution
- 6In the following questions, match column $-I$ with column $-II$ and choose the correct optionsView Solution
- 7View SolutionFor the system given below, find the angular frequency of oscillation ?
- 8A particle starts oscillating simple harmonically from its equilibrium position then, the ratio of kinetic energy and potential energy of the particle at the time $T/12$ is : ($T =$ time period)View Solution
- 9The period of a simple pendulum measured inside a stationary lift is found to be $T$. If the lift starts accelerating upwards with acceleration of $g/3,$ then the time period of the pendulum isView Solution
- 10The displacement of a particle executing simple harmonic motion is given byView Solution
$\mathrm{y}=\mathrm{A}_{0}+\mathrm{A} \sin \omega \mathrm{t}+\mathrm{B} \cos \omega \mathrm{t}$
Then the amplitude of its oscillation is given by