Question
A pendulum oscillates $40$ times in $4$ seconds. Find its time period and frequency.

Answer

The time required to complete one oscillation is known as time period. It is given by the inverse of the frequency.
Number of oscillation $= 40$
Total time taken $= 4$ seconds
Time period = time taken in one oscillation$=\frac{\text{tota time}}{\text{total number of oscillation}}$
$=\frac{4\ \text{seconds}}{40}$
$=\frac{1}{10}\text{second}$
$=0.1$ second
Frequency of oscillations is defined as the number of oscillations of a vibrating body per second.
It is given by$\text{Frequency}=\frac{\text{Number of oscillations}}{\text{Total time }}=\frac{40}{4}=10\ \text{H}_{\text{z}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free