A pendulum with time period of $1\, s$ is losing energy due to damping. At certain time its energy is $45\, J$. If after completing $15\,oscillations$ , its energy has become $15\, J$, its damping constant (in $s^{-1}$ ) is
JEE MAIN 2015, Medium
Download our app for free and get started
As we know, $E=E_{0} e^{-\frac{b t}{m}}$
$15=45 e^{-\frac{b 15}{m}}$
[As no. of oscillations $=15 \text { so } t=15 \mathrm{sec}]$
$\frac{1}{3}=e^{-\frac{b 15}{m}}$
Taking log on both sides
$\frac{b}{m}=\frac{1}{15} \ell \mathrm{n} 3$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Two pendulums have time periods $T$ and $\frac{{5T}}{4}.$They start $S.H.M.$ at the same time from the mean position. What will be the phase difference between them after the bigger pendulum has complete one oscillation ..... $^o$
A pendulum has time period $T$. If it is taken on to another planet having acceleration due to gravity half and mass $ 9 $ times that of the earth then its time period on the other planet will be
A bar of mass $m$ is suspended horizontally on two vertical springs of spring constant $k$ and $3k$ . The bar bounces up and down while remaining horizontal. Find the time period of oscillation of the bar (Neglect mass of springs and friction everywhere).