$f =\left(\frac{330+15}{330-15}\right) \times f _0$
$=\frac{345}{315} f _0$
$\frac{345}{315} f _0- f _0=40$
$\frac{30}{315} f _0=40$
$f _0=\frac{4 \times 315}{3}=420\,Hz$
$(A)$ $u=0.8 v$ and $f_5=f_0$
$(B)$ $u=0.8 v$ and $f_5=2 f_0$
$(C)$ $u=0.8 v$ and $f_5=0.5 f_0$
$(D)$ $u=0.5 v$ and $f_5=1.5 f_0$
