A person with his hand in his pocket is skating on ice at the rate of $10 m / s$ and describes a circle of radius $50 m$. What is his inclination to vertical: $\left( g =10 m / sec ^2\right)$
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(b)
Since surface $(ice)$ is frictionless, so the centripetal force required for skating will be provided by inclination of boy with the vertical and that angle is given as $\tan \theta=\frac{v^2}{r g}$ where $v$ is speed of skating and $r$ is radius of circle in which he moves.
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