MCQ
A physical quantity $'x'$ is calculated from the relation $x = \frac{{{a^2}{b^3}}}{{c\sqrt d }}$ in $a$,$b$,$c$ and $d$ are $2\%$, $1 \%$, $3\%$ and $4\%$ respectively, what is the percentage error in $x$.
  • A
    $ \pm 11\%$
  • B
    $ \pm 13\%$
  • $ \pm 12\%$
  • D
    $ \pm 14\%$

Answer

Correct option: C.
$ \pm 12\%$
c
$A =\frac{ a ^{2} b ^{3}}{ c \sqrt{ d }}$

$\frac{\Delta a }{ a } \times 100=1 \%,$$ \frac{\Delta b }{ b } \times 100=3 \%,$$ \frac{\Delta c }{ c } \times 100=2 \%$ and $\frac{\Delta d }{ d } \times 100=2 \%$

$\frac{\Delta A }{ A } \times 100=2 \frac{\Delta a }{ a } \times 100+3 \frac{\Delta b }{ b } \times 100+$$\frac{\Delta c }{ c } \times 100+\frac{1}{2} \times \frac{\Delta d }{ d } \times 100$

$\frac{\Delta A }{ A } \times 100=2 \times 2+3 \times 1+3+\frac{1}{2} \times 4=12 \%$

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