A piece of fuse wire melts when a current of $15\, ampere$ flows through it. With this current, if it dissipates $22.5\, W$, the resistance of fuse wire will be .............. $\Omega$
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(d) $P = {i^2}R$ $ \Rightarrow $ $22.5 = {(15)^2} \times R$ $ \Rightarrow $ $R = 0.10\,\,\Omega $
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