A dc source of emf ,E_1 = 100,V and internal resistance r = 0.5,Omega , a storage battery of emf E

Q: A $dc$ source of $emf \,E_1 = 100\,V$ and internal resistance $r = 0.5\,\Omega ,$ a storage battery of emf $E_2 = 90\,V$ and an external resistance $R$ are connected as shown in figure. For what value of $R$ no current will pass through the battery ? ................ $\Omega$

c $\frac{100}{R+r}=\frac{90}{R}$ $\Rightarrow \frac{R+r}{R}=\frac{10}{9}$ $\Rightarrow \quad 1+\frac{0.5}{\mathrm{R}}=\frac{10}{9}$ $\Rightarrow \quad \frac{0.5}{\mathrm{R}}=\frac{1}{9}$ $\therefore R=4.5 \,\Omega$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A $dc$ source of $emf \,E_1 = 100\,V$ and internal resistance $r = 0.5\,\Omega ,$ a storage battery of emf $E_2 = 90\,V$ and an external resistance $R$ are connected as shown in figure. For what value of $R$ no current will pass through the battery ? ................ $\Omega$

A$5.5$
B$3.5$
C$4.5$
D$2.5$

JEE MAIN 2013, Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free