${\lambda _m}T = constant$
${\lambda _m} = \frac{{constant}}{T}$
So when a piece of iron is heated, ${\lambda _m}$ decreases $i.e.,$ with rise in temperature the maximum intensity of radiation emitted gets shifted towards the shorter wavelengths. So the colour of the heated object will change that of longer wavelength $(red)$ to that of shorter $(reddish\,yellow)$ and when the temperature is sufficiently high and all wavelengths are emitted, the colour will become white.


$(A)$ heat flow through $A$ and $E$ slabs are same.
$(B)$ heat flow through slab $E$ is maximum.
$(C)$ temperature difference across slab $E$ is smallest.
$(D)$ heat flow through $C =$ heat flow through $B +$ heat flow through $D$.
| Column $I$ | Column $II$ |
| $(A)$ Bimetallic strip | $(p)$ Radiation from a hot body |
| $(B)$ Steam engine | $(q)$ Energy conversion |
| $(C)$ Incandescent lamp | $(r)$ Melting |
| $(D)$ Electric fuse | $(s)$ Thermal expansion of solids |