Speed of air over the lower wing, $V_{1}=180 km / h =50 m / s$

Speed of air over the upper wing, $V_{2}=234 km / h =65 m / s$

Density of air, $\rho=1 kg m ^{-3}$

Pressure of air over the lower wing $=P_{1}$

Pressure of air over the upper wing $=P_{2}$

The upward force on the plane can be obtained using Bernoulli's equation as:

$P_{1}+\frac{1}{2} \rho V_{1}^{2}=P_{2}+\frac{1}{2} \rho V_{2}^{2}$

$P_{1}-P_{2}=\frac{1}{2} \rho\left(V_{2}^{2}-V_{1}^{2}\right)$

The upward force ($F$) on the plane can be calculated as:

$\left(P_{1}-P_{2}\right) A$

$=\frac{1}{2} \rho\left(V_{2}^{2}-V_{1}^{2}\right) A$

$=\frac{1}{2} \times 1 \times\left((65)^{2}-(50)^{2}\right) \times 50$

$=43125 N$

Using Newton's force equation, we can obtain the mass $(m)$ of the plane as:

$F=m g$

$\therefore m=\frac{43125}{9.8}$

$=4400.51 kg$

$\sim 4400 kg$

Hence, the mass of the plane is about $4400\; kg$.