MCQ
A plane polarized light is incident on a polariser with its pass axis making angle $\theta$ with $x-$ axis, as shown in the figure. At four different values of $\theta$, $\theta\, = 8^o, 38^o, 188^o$ and $218^o$, the observed intensities are same. What is the angle between the direction of polarization and $x-$ axis.....$^o$
  • $203$
  • B
    $45$
  • C
    $98$
  • D
    $128$

Answer

Correct option: A.
$203$
a
Let the angle between polarization direction and $x$ -axis be $\theta^{\prime}$

So angle between polarisation direction and pass axis of polariser is $\left(\theta^{\prime}-\theta\right)$

Given $\theta  = {8^o},{88^o},\,{188^o},\,\,{218^o}$

$\therefore I=I_{o} \cos ^{2}\,\left(\theta^{\prime}-\theta\right)$

For $\theta^{\prime}=203^o$ intensities are same

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