i.e. liquid is rarer than air for sound waves
Angle of total internal reflection (critical angle)
$=\sin ^{-1}\left(\frac{\mathrm{v}_{\mathrm{liq}}}{\mathrm{v}_{\mathrm{air}}}\right)=\sin ^{-1}\left(\frac{1}{2}\right)=30^{\circ}$
Hence sound wave is totally reflected back.


${z_1} = a\cos (kx - \omega \,t)$.....$(A)$
${z_2} = a\cos (kx + \omega \,t)$.....$(B)$
${z_3} = a\cos (ky - \omega \,t)$..... $(C)$