MCQ
A planet revolves around sun whose mean distance is $1.588$ times the mean distance between earth and sun. The revolution time of planet will be
- A$1.25$ years
- B$1.59$ years
- C$0.89$ years
- ✓$2$ years
✓
Answer
Correct option: D.
$2$ years
$\frac{T_{\text {plant }}}{T_{\text {earth }}}=\left(\frac{r_{\text {plant }}}{r_{\text {earth }}}\right)^{3 / 2}=(1.588)^{3 / 2}=2$
$ \therefore T_{\text {planet }}=2$ year
$ \therefore T_{\text {planet }}=2$ year
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