MCQ
A planet revolves around sun whose mean distance is $1.588$ times the mean distance between earth and sun. The revolution time of planet will be ........... $ years$
- A$1.25$
- B$1.59$
- C$0.89$
- ✓$2$
✓
Answer
Correct option: D.
$2$
d
(d)$\frac{{{T_{{\rm{plant}}}}}}{{{T_{{\rm{earth}}}}}} = {\left( {\frac{{{r_{{\rm{plant}}}}}}{{{r_{{\rm{earth}}}}}}} \right)^{3/2}} = {(1.588)^{3/2}} = 2$
${T_{{\rm{planet}}}} = 2\;year$
(d)$\frac{{{T_{{\rm{plant}}}}}}{{{T_{{\rm{earth}}}}}} = {\left( {\frac{{{r_{{\rm{plant}}}}}}{{{r_{{\rm{earth}}}}}}} \right)^{3/2}} = {(1.588)^{3/2}} = 2$
${T_{{\rm{planet}}}} = 2\;year$
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