MCQ
A particle of mass $250\,g$ executes a simple harmonic motion under a periodic force $F =(-25\,x) N$. The particle attains a maximum speed of $4\,m / s$ during its oscillation. The amplitude of the motion is $...........cm$.
  • A
    $20$
  • $40$
  • C
    $60$
  • D
    $80$

Answer

Correct option: B.
$40$
b
$\frac{1}{4} a =-25 x \quad ; \quad a =-100 x$

$\omega^2=100 \quad \omega=10$

$\omega A =4$ $\quad A=\frac{4}{10}=0.4\,m$

$A =40\,cm$

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