A plank with a small block on top of it is under going vertical $SHM$ . Its period is $2\ sec$ . The minimum amplitude at which the block will separate from plank is
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Here $\mathrm{g}=\mathrm{A} \omega^{2}$
$\therefore \quad A=\frac{g}{\omega^{2}}=\frac{g}{\left(\frac{2 \pi}{T}\right)^{2}}=\frac{g T^{2}}{4 \pi^{2}}$
$\mathrm{A}=\frac{10 \times 4}{4 \pi^{2}}=\frac{10}{\pi^{2}} \mathrm{m}$
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