A point charge + q is placed at the origin. A second point charge… - Vidyadip

MCQ

A point charge + q is placed at the origin. A second point charge +9 q is placed at $( d , 0,0)$ in Cartesian coordinate system. The point in between them where the electric field vanishes is :

A
$(4 d / 3,0,0)$
✓
$( d / 4,0,0)$
C
$(3 d / 4,0,0)$
D
$( d / 3,0,0)$

✓

Answer

Correct option: B.

$( d / 4,0,0)$

(B) $( d / 4,0,0)$
Explanation:

Let $E _{ p }=0$
$\begin{array}{l}\therefore \frac{kq}{x^2}=\frac{k 9 q}{(d-x)^2} \\
\Rightarrow \frac{d-x}{x}=3 \Rightarrow x=\frac{d}{4}\end{array}$
$\therefore$ co-ordinate of P is $\left(\frac{ d }{4}, 0,0\right)$

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