MCQ
A polariser is used to
- AReduce intensity of light
- ✓Produce polarised light
- CIncrease intensity of light
- DProduce unpolarised light
✓
Answer
Correct option: B.
Produce polarised light
b
(b)Polariser produced prolarised light.
(b)Polariser produced prolarised light.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In a $LCR$ circuit capacitance is changed from $C$ to $2C$. For the resonant frequency to remain unchanged, the inductance should be change from $L$ to
→In a dark room of photography, generally red light is used. The reason is
The resistances of a wire at temperatures $t\,^oC$ and $0\,^oC$ are related by
→Hydrogen atom does not emit X-rays because
A battery of internal resistance $4\,\Omega $ is connected to the network of the resistance as shown in Fig. If the maximum power can be delivered to the network, the magnitude of $R$ in $\Omega $ should be
→A metal wire of resistance $3\,\Omega $ is elongated to make a uniform wire of double its previous length. The new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle $60^o$ at the centre, the equivalent resistance between these two points will be
→The electric field inside a conductor.
A convex lens of focal length $84 cm$ is in contact with a concave lens of focal length $12 cm.$ The power of combination (in diopters) is
→According to Einstein's interpretation of the photoelectric effect, the maximum $K.E.$ of photoelectrons depends on $( h -W)$ where is the frequency of incident radiation and $W$ is the work function. For three different metals graph plotted between maximum $K/E.$ and the frequency of incident radiations. The three graphs obtained:
→Find equivalent capacitance across $AB$.....$ \mu F$ (all capacitances in $\mu F$)
→