MCQ
A pole $6 m$ high casts a shadow $2 \sqrt{3} m$ long on the ground, then the sun's elevation is
  • A
    $30^{\circ}$
  • $60^{\circ}$
  • C
    $45^{\circ}$
  • D
    $90^{\circ}$

Answer

Correct option: B.
$60^{\circ}$
Let height $=6 m$
length of shadow $=2 \sqrt{3 m}$
$\theta$ is angle of elevation
$\tan \theta=\text { (height) } / \text { (shadow length) }$
$=\frac{6}{2} \sqrt{3}=\sqrt{3}$
$\theta=\frac{\pi}{3}$
Angle of inclination is $=60^{\circ}$

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