Question
A projectile is moving at $20\,m/sec$ at its highest point where it breaks into two equal parts due to an internal explosion. One part moves vertically up at $30\,m/sec$ . Then the other part will move at ............. $\mathrm{m}/ \mathrm{s}$

Answer

$\mathrm{mv} \cos \theta=2 \mathrm{m} \times 20$

$vcos$ $\theta=40 \ldots \ldots(1)$

$m v \sin \theta=m \times 30$

$v \sin \theta=30$   $...(2)$

by equation $(1)$$\&(2)$

$V=\sqrt{(30)^{2}+(40)^{2}}=50 \mathrm{m} / \mathrm{s}$

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