MCQ
A projectile is projected with speed $u$ of an angle of $60^o$ with horizontal from the foot of an inclined plane. If the projectile hits the inclined plane horizontally, the range on inclined plane will be :-
  • A
    $\frac{{{u^2}\sqrt {21} }}{{2g}}$
  • B
    $\frac{{3{u^2}}}{{4g}}$
  • C
    $\frac{{{u^2}}}{{8g}}$
  • $\frac{{\sqrt {21} }}{8}\frac{{{u^2}}}{g}$

Answer

Correct option: D.
$\frac{{\sqrt {21} }}{8}\frac{{{u^2}}}{g}$
d
Range on the inclined plane

$=\sqrt{h_{\max }^{2}+\left(\frac{R}{2}\right)^{2}}=\frac{u^{2}}{g} \frac{\sqrt{21}}{8}$

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