MCQ
A proton, a deuteron and an α particle are accelerated through same potential difference and then they enter in a normal uniform magnetic field, the ratio of their kinetic energies will be:
- A$2 : 1 : 3$
- ✓$1 : 1 : 2$
- C$1 : 1 : 1$
- D$1 : 2 : 4$
✓
Answer
Correct option: B.
$1 : 1 : 2$
Kinetic energy obtained $= qV$ where $q$ is the charge and $V$ is the potential through which the particle is accelerated.
Also, the force due to the magnetic field is perpendicular to the direction of motion.
So it cant change the speed and consequentially Kinetic energy of the particles will remain same after they enter a normal magnetic field.
In the above problem, $V$ is constant.
So $\text{KE}\propto\text{q}.$
The charges of the proton, deuteron and the alpha particle are in the ratio $1 : 1 : 2$
So, their kinetic energies are in the ratio $1 : 1 : 2$
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