Question
A proton, a neutron, an electron and an $\alpha\,-$particle have same energy. If $\lambda_{ p }, \lambda_{ n }, \lambda_{ e }$ and $\lambda_{\alpha}$ are the de Broglie's wavelengths of proton, neutron, electron and $\alpha$ particle respectively, then choose the correct relation from the following

Answer

$\lambda=\frac{ h }{\sqrt{2 Em }}$

$\lambda \propto \frac{1}{\sqrt{ m }}$

$\therefore\lambda_{ e }>\lambda_{ p }>\lambda_{ n }>\lambda_{\alpha}$

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