MCQ
A proton and an $\alpha$ -particle are accelerated through a potential difference of $100\, V$. The ratio of the wavelength associated with the proton to that associated with an $\alpha$ -particle is
- A$\sqrt 2 : 1$
- B$2 : 1$
- ✓$2 \sqrt{2} : 1$
- D$\frac{1}{2 \sqrt{2}} : 1$



