MCQ
A proton is about $1840$ times heavier than an electron. When it is accelerated by a potential difference of $1\, kV$, its kinetic energy will be......$keV$
- A$1840$
- B$1/1840$
- ✓$1$
- D$920$
✓
Answer
Correct option: C.
$1$
c
(c) $KE = QV = e \times 10^3 \,V = 1\,KeV.$
(c) $KE = QV = e \times 10^3 \,V = 1\,KeV.$
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