(D) $x^2-5 x+6=0$ Explanation: since 3 is the root of the equation, x = 3 must satisfy the equation. Applying x = 3 in the equation $x^2-5 x+6=0$ gives, $(3)^2-5(3)+6=0$ $\Rightarrow 9-15+6=0$ $\Rightarrow 15-15=0$ $\Rightarrow 0=0$ $\Rightarrow$ L.H.S. = R.H.S. Hence, $x^2-5 x+6=0$ is a required equation which has 3 as root.
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