MCQ
A quantity of $PC{l_5}$ was heated in a $10$ litre vessel at ${250\,^o}C$; $PC{l_5}_{(g)}$ $\rightleftharpoons$ $PC{l_3}_{(g)} + C{l_2}_{(g)}$. At equilibrium the vessel contains $0.1$ $mole$ of $PC{l_5}\,0.20$ $mole$ of $PC{l_3}$ and $0.2$ $mole$ of $C{l_2}$. The equilibrium constant of the reaction is
  • A
    $0.02$
  • B
    $0.05$
  • $0.04$
  • D
    $0.025$

Answer

Correct option: C.
$0.04$
(c) ${{K}_{c}}=\frac{[PC{{l}_{3}}]\,\,[C{{l}_{2}}]}{[PC{{l}_{5}}]}=\frac{\frac{0.2}{10}\times \frac{0.2}{10}}{\left[ {0.1}/{10}\; \right]}=0.04$

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