1. A radioactive nucleus 'A' undergoes a series of decays as give… - Vidyadip

Question

A radioactive nucleus 'A' undergoes a series of decays as given below:

$\text{A}\xrightarrow\alpha\text{A}_1\xrightarrow\beta\text{A}_2\xrightarrow\alpha\text{A}_3\xrightarrow\gamma\text{A}_4$

The mass number and atomic number of $A_2$ are 176 and 71 respectively. Determine the mass and atomic numbers of $A_4$ and A.

Write the basic nuclear process underlying $\beta+$ and $\beta-$ decays.

✓

Answer

$\text{A}^{180}_{74}\xrightarrow\alpha\text{A}^{176}_{72}\xrightarrow\beta\text{A}^{176}_{71}\xrightarrow\alpha\text{A}^{172}_{69}\xrightarrow\gamma\text{A}^{172}_{69}$
The mass number and atomic number of $A_4$ is 172 and 69, respectively.
The mass number and atomic number of A is 180 and 74, respectively.
Basic process underlying $\beta+$ and $\beta-$ decay are
During a weak interaction an atomic nucleus converts into a nucleus with one higher atomic number while emitting one electron and an electron antineutrino this is called beta minus decay.
$X^A_Z\rightarrow Y^A_{Z+1}+e^-+\bar{ve}$
During a weak interaction an atomic nucleus converts into a nucleus with one lower number while emitting a positron and electron neutrino this is called beta Plus decay.
$X^A_Z\rightarrow Y^A_{Z-1}+e^++\bar{ve}$

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