MCQ
A reaction is $A + B \to C + D$. Initially we start with equal concentration of $A$ and $B$. At equilibrium we find the moles of $C$ is two times of $A$. What is the equilibrium constant of the reaction
- ✓$4$
- B$2$
- C$0.25$
- D$0.5$
✓
Answer
Correct option: A.
$4$
(a) $A+ B$ $ \rightleftharpoons $ $C+ D$
at equilibrium $a$ $a$ $2a$ $2a$
$K = \frac{{2a \times 2a}}{{a \times a}} = 4$
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