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A reaction rate constant is given by $k = 1.2 \times {10^{14}}{e^{ - (25000/RT)}}\,{\sec ^{ - 1}}$ It means

• A
  $\log \,k$ versus $\log \,T$ will give a straight line with slope as $-25000$
• B
  $\log \,k$ versus $T$ will give a straight line with slope as $-25000$
• C
  $\log \,k$ versus $\log \,1/T$ will give a straight line with slope as $-25000$
• ✓
  $\log \,k$ versus $1/T$ will give a straight line