Question
A rectangular loop of wire hanging vertically with one end in a uniform magnetic field $\vec{B}$, supports a small block of mass $m . \vec{B}$ points into the page in the shaded region of below figure. For what current I in the loop would the magnetic force exactly balance the downward gravitational force?
Image

Answer

The magnetic force on the horizontal segment of the loop inside the field must be upward to balance the downward gravitational force.
With $\vec{B}$ pointing into the page, the current in that segment must be toward the right so that $\vec{F}=\vec{L} \times \vec{B}$ on that segment points upward.
That is, the current in the loop must be clockwise.
Taking $L=a, F=l a B$
$\therefore laB = mg$
$\therefore I =\frac{m g}{a B}$
is the required expression for the current.

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